P=100-20X+1x^2

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Solution for P=100-20X+1x^2 equation: 



=100-20P+1P^2

We move all terms to the left:

-(100-20P+1P^2)=0

We get rid of parentheses

-1P^2+20P-100=0

a = -1; b = 20; c = -100;
Δ = b2-4ac
Δ = 202-4·(-1)·(-100)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$P=\frac{-b}{2a}=\frac{-20}{-2}=+10$

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